Implement Stack using Queue(s) Problem
Leetcode Lesson: Implement Stack using Queues
1. Problem Statement
Implement a last-in-first-out (LIFO) stack using only two queues. The implemented stack should support all the functions of a normal stack (push
, pop
, top
, empty
).
Implement the MyStack
class:
push(x)
Pushes element x to the top of the stack.pop()
Removes the element on the top of the stack and returns it.top()
Returns the element on the top of the stack.empty()
Returnstrue
if the stack is empty,false
otherwise.
Notes:
- You must use only standard queue operations, which means only
push to back
,peek/pop from front
,size
, andis empty
are valid. - Depending on your language, the queue may not be supported natively. You may simulate a queue using a list or deque (double-ended queue), as long as you use only a queue's standard operations.
2. Conceptual Understanding
This problem challenges us to implement a stack (LIFO - Last In, First Out) data structure using only queue (FIFO - First In, First Out) operations. It's like trying to create a stack of plates (where you add and remove from the top) using only queues (where you add to the back and remove from the front).
The key is to find a way to reverse the order of elements when needed, as stacks and queues have opposite ordering principles.
3. Approach Brainstorming
We can consider two main approaches:
- Make push operation costly: Keep the elements in the correct stack order, but make pushing a new element expensive.
- Make pop operation costly: Allow pushing to be simple, but make popping an element more complex.
We'll focus on making the push operation costly, as it provides a more straightforward implementation for the other operations.
4. Optimal Solution Walkthrough
Here's how we can implement the stack using two queues:
- Use two queues:
q1
andq2
. - For
push
operation:- Add the new element to
q2
. - Move all elements from
q1
toq2
. - Swap
q1
andq2
.
- Add the new element to
- For
pop
,top
, andempty
operations:- Perform these operations directly on
q1
.
- Perform these operations directly on
This approach ensures that q1
always has the elements in the correct stack order (newest on top).
5. Python Implementation
from queue import Queue
class MyStack:
def __init__(self):
self.q1 = Queue()
self.q2 = Queue()
def push(self, x: int) -> None:
self.q2.put(x)
while not self.q1.empty():
self.q2.put(self.q1.get())
self.q1, self.q2 = self.q2, self.q1
def pop(self) -> int:
return self.q1.get()
def top(self) -> int:
return self.q1.queue[0]
def empty(self) -> bool:
return self.q1.empty()
- We use Python's
Queue
class for our queues. push
adds the new element toq2
, moves all elements fromq1
toq2
, then swapsq1
andq2
.pop
andtop
operate directly onq1
.empty
checks ifq1
is empty.
6. Time and Space Complexity Analysis
Time Complexity:
push
: O(n), where n is the number of elements in the stackpop
: O(1)top
: O(1)empty
: O(1)
Space Complexity: O(n), where n is the number of elements in the stack
The push operation is costly in terms of time, but this allows other operations to be very efficient.
7. Edge Cases and Testing
Consider these test cases:
- Push multiple elements, then pop all
- Push, pop, push again
- Check top after multiple pushes
- Check empty on a new stack and after operations
- Push, pop, check empty, push again
8. Common Pitfalls and Mistakes
- Forgetting to swap queues after push operation
- Implementing pop or top incorrectly when the stack is empty
- Using list methods instead of queue methods
9. Optimization Opportunities
- We could use a single queue instead of two, rotating the queue after each push operation.
- If many consecutive push operations are expected, we could optimize by delaying the reordering until a pop or top operation is called.
10. Related Problems and Concepts
- "Implement Queue using Stacks" (reverse problem)
- Understanding of stack and queue data structures
- Adapter design pattern (adapting one interface to another)
11. Reflection Questions
- How would the implementation change if we made the pop operation costly instead of push?
- Can you think of a real-world scenario where you might need to implement a stack interface using queue-like operations?
- How does this implementation compare to a native stack implementation in terms of efficiency?